This is a blog for all of Mr. James' math classes at HTHS. This is for weekly updates for AP Calculus, Calculus, and Pre-AP Pre-Calculus. This blog is also used to discuss anything pertaining to these classes.
Friday, August 21, 2009
5th Period Test 1
Everyone from 5rd period, this is where you need to comment with your solutions to the problems.
Since 4 and 324 have the same root, fourth root, they can be multiplied together. When they are, you get 1296^(1/4). Therefore, 6 x 6 x 6 x 6 is equivalent to 1296.
12 comments:
pg 131 #36
6x^2+x-12
(3x-4)(2x+3)
#125
Find an equation for the line that has x-intercept 4 and y-intercept 12
y=3x+12
pg 131 #20
(a^2)^-3(a^3b)^2(b^3)^4
(a^0)(b^14)
(b^14)
Page 131 #16:
4^(1/4) x 324^(1/4) = 1296^(1/4)= 6
Since 4 and 324 have the same root, fourth root, they can be multiplied together. When they are, you get 1296^(1/4). Therefore, 6 x 6 x 6 x 6 is equivalent to 1296.
page 133 #98
x^3-4x^2-5x>2
-2>x^3-4x^2-5x>2
-2>x(x-5)(x+1)>2
-2>x=0,-1,5>2
x=(0,-1)
Page 131 #60
(1/x+2)+(1/x^2-4)-(2/x^2-x-2)
(x-2)(x+1)+(x+1)-(2x+4)/(x+2)(x-2)(x+1)
-(x+3)/(x+2)
x^2-2x-3 (x-3)(x+1)
-------- ---------
2x^2+5x+3 (2x+3)(x+1)
The (x+1)'s cancel out and you're left with
x-3
----
2x+3
the problem was #54
pg 131 #10
1- |1 -|-1||
1-|1-1|
1-0
1
#22
((r^2s^4/3)/(r^1/3s))^6
.......................
r^10s^2
Nolan, you need to check your slope again.
Chloe, I don't follow how the inequality turned into an equality. Is your answer the interval notation?
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